| // Ceres Solver - A fast non-linear least squares minimizer |
| // Copyright 2023 Google Inc. All rights reserved. |
| // http://ceres-solver.org/ |
| // |
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| // modification, are permitted provided that the following conditions are met: |
| // |
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| // |
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| // |
| // Author: keir@google.com (Keir Mierle) |
| // |
| // A simple example of using the Ceres minimizer. |
| // |
| // Minimize 0.5 (10 - x)^2 using jacobian matrix computed using |
| // automatic differentiation. |
| |
| #include "absl/log/initialize.h" |
| #include "ceres/ceres.h" |
| |
| // A templated cost functor that implements the residual r = 10 - |
| // x. The method operator() is templated so that we can then use an |
| // automatic differentiation wrapper around it to generate its |
| // derivatives. |
| struct CostFunctor { |
| template <typename T> |
| bool operator()(const T* const x, T* residual) const { |
| residual[0] = 10.0 - x[0]; |
| return true; |
| } |
| }; |
| |
| int main(int argc, char** argv) { |
| absl::InitializeLog(); |
| |
| // The variable to solve for with its initial value. It will be |
| // mutated in place by the solver. |
| double x = 0.5; |
| const double initial_x = x; |
| |
| // Build the problem. |
| ceres::Problem problem; |
| |
| // Set up the only cost function (also known as residual). This uses |
| // auto-differentiation to obtain the derivative (jacobian). |
| ceres::CostFunction* cost_function = |
| new ceres::AutoDiffCostFunction<CostFunctor, 1, 1>(); |
| problem.AddResidualBlock(cost_function, nullptr, &x); |
| |
| // Run the solver! |
| ceres::Solver::Options options; |
| options.minimizer_progress_to_stdout = true; |
| ceres::Solver::Summary summary; |
| ceres::Solve(options, &problem, &summary); |
| |
| std::cout << summary.BriefReport() << "\n"; |
| std::cout << "x : " << initial_x << " -> " << x << "\n"; |
| return 0; |
| } |