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Keir Mierle8ebb0732012-04-30 23:09:08 -07001// Ceres Solver - A fast non-linear least squares minimizer
2// Copyright 2010, 2011, 2012 Google Inc. All rights reserved.
3// http://code.google.com/p/ceres-solver/
4//
5// Redistribution and use in source and binary forms, with or without
6// modification, are permitted provided that the following conditions are met:
7//
8// * Redistributions of source code must retain the above copyright notice,
9// this list of conditions and the following disclaimer.
10// * Redistributions in binary form must reproduce the above copyright notice,
11// this list of conditions and the following disclaimer in the documentation
12// and/or other materials provided with the distribution.
13// * Neither the name of Google Inc. nor the names of its contributors may be
14// used to endorse or promote products derived from this software without
15// specific prior written permission.
16//
17// THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS"
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28//
29// Author: keir@google.com (Keir Mierle)
30//
31// Minimize 0.5 (10 - x)^2 using jacobian matrix computed using
32// numeric differentiation.
33
Keir Mierle8ebb0732012-04-30 23:09:08 -070034#include "ceres/ceres.h"
Keir Mierleefe7ac62012-06-24 22:25:28 -070035#include "glog/logging.h"
Keir Mierle8ebb0732012-04-30 23:09:08 -070036
37using ceres::NumericDiffCostFunction;
38using ceres::CENTRAL;
Keir Mierle8ebb0732012-04-30 23:09:08 -070039using ceres::CostFunction;
40using ceres::Problem;
41using ceres::Solver;
42using ceres::Solve;
43
Sameer Agarwale837aea2013-01-21 13:05:01 -080044// A cost functor that implements the residual r = 10 - x.
Sameer Agarwal085cd4a2013-02-06 14:31:07 -080045struct CostFunctor {
Sameer Agarwale837aea2013-01-21 13:05:01 -080046 bool operator()(const double* const x, double* residual) const {
47 residual[0] = 10.0 - x[0];
Keir Mierle8ebb0732012-04-30 23:09:08 -070048 return true;
49 }
50};
51
52int main(int argc, char** argv) {
Keir Mierle8ebb0732012-04-30 23:09:08 -070053 google::InitGoogleLogging(argv[0]);
54
Sameer Agarwal085cd4a2013-02-06 14:31:07 -080055 // The variable to solve for with its initial value. It will be
56 // mutated in place by the solver.
57 double x = 0.5;
58 const double initial_x = x;
Keir Mierle8ebb0732012-04-30 23:09:08 -070059
60 // Build the problem.
61 Problem problem;
Sameer Agarwal085cd4a2013-02-06 14:31:07 -080062
63 // Set up the only cost function (also known as residual). This uses
64 // numeric differentiation to obtain the derivative (jacobian).
65 CostFunction* cost_function =
66 new NumericDiffCostFunction<CostFunctor, CENTRAL, 1, 1> (new CostFunctor);
67 problem.AddResidualBlock(cost_function, NULL, &x);
Keir Mierle8ebb0732012-04-30 23:09:08 -070068
69 // Run the solver!
70 Solver::Options options;
Keir Mierle8ebb0732012-04-30 23:09:08 -070071 options.minimizer_progress_to_stdout = true;
72 Solver::Summary summary;
73 Solve(options, &problem, &summary);
Sameer Agarwal085cd4a2013-02-06 14:31:07 -080074
Keir Mierle8ebb0732012-04-30 23:09:08 -070075 std::cout << summary.BriefReport() << "\n";
76 std::cout << "x : " << initial_x
77 << " -> " << x << "\n";
78 return 0;
79}